Question

How do you graph the function and its inverse of `f(x)=absx+1`?

Answer 1

See explanation...

Explanation:

The graph of `f(x) = abs(x)+1` is a 'V' shape with slope `+-1` and vertex at `(0, 1)`:

graph{abs(x)+1 [-10, 10, -5, 5]}

The graph of the inverse relation (it is not a function) is formed by reflecting the above graph in the `y=x` line:

graph{x=abs(y)+1 [-10, 10, -5, 5]}

For any `x > 1` this relation has two possible `y` values, so fails the vertical line test and is not a function.