An angle is 10 more than the measure of its complement. What are the number of degrees in each angle?

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Answer 1 · 2016-12-24T05:06:48

#m/_A = x = 40#
#m/_B = x+10= 50#

Complimentary angles have a sum of #90^o#

#m/_A + m/_B = 90^o#

#m/_A = x#
#m/_B = x+10#
10 more than the measure of its complement

#x + x + 10 = 90^o#

#2x + 10 = 90^o#

#2x cancel(+ 10) cancel (-10) = 90^o - 10#

#2x=80^o#

#(cancel2x)/(cancel2) =80/2#

#x = 40#
#x+10 = 50#