How do you solve #\frac { j } { 5} - 14= - 9#?

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Answer 1 · 2016-12-26T03:06:38

#j = 25#

First, we can isolate the #j# term by adding #color(red)(14)# to each side of the equation which will also keep the equation balanced:

#j/5 - 14 +color(red)(14) = -9 + color(red)(14)#

#j/5 - 0 = 5#

#j/5 = 5#

Next, to solve for #j# we can multiple each side of the equation by #color(blue)(5)# which will again keep the equation balanced:

#color(blue)(5) xx j/5 = color(blue)(5) xx 5#

#cancel(color(blue)(5)) xx j/color(blue)(cancel(color(black)(5))) = 25#

#j = 25#