How do you solve #5*6^(3m)=20#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer CW Dec 26, 2016 #m=0.2579# Explanation: #5*6^(3m)=20# #=> 6^(3m)=20/5=4# take log of both sides: #log6^(3m)=log4# #=> 3mlog6=log4# #=> 3m=log4/log6=0.7737# #=> m=0.7737/3=0.2579# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 3708 views around the world You can reuse this answer Creative Commons License