How do you solve #(10h)/108=5/9#?

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Answer 1 · 2016-12-26T19:05:21

#10/108h=5/9#

Multiply each side by the reciprocal of the coefficient of h. The coefficient of h is #10/108#, so the reciprocal is #108/10#

#h=(5/9)*(108/10)#

#h=(1/1)*(12/2)#

#h=6#

Answer 2 · 2016-12-26T19:11:47

#h = 6#

#(10h)/108 = 5/9" "larr# isolate #h# by #xx 108/10# on both sides

#108/10 xx(10h)/108 = 108/10xx5/9#

#h= cancel108^12/cancel10^2xxcancel5/cancel9#

#h = 6#

Notice that cancelling first avoids ending up with

#h = 540/90#