Question

How do you evaluate the limit `lim(x^2-36)/(x+6)dx` as `x->1`?

Answer 1

`lim_(x -> 1) (x^2-36) /( x+6) = -5`

Explanation:

Simply evaluate the expression at 1. `(1^2 - 36)/(1+6) = -35/7 = -5`