Question

How do you solve `5( x + 2) ^ { 2} - 3= 28`?

Answer 1

`x=+-sqrt(31/5)-2`

Explanation:

Given -

`5(x+2)^2-3=28`
`5(x+2)^2=28+3`
`5(x+2)^2=31`
`(x+2)^2=31/5`
`sqrt((x+2)^2)=+-sqrt(31/5)`

`x+2=+-sqrt(31/5)`
`x=+-sqrt(31/5)-2`