How do you simplify #(4x y ^ { 2} ) ^ { 3}#?

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Answer 1 · 2016-12-28T03:44:44

#64x^3y^6#

To simplify this we need to utilize two rules of exponents:

#color(red)((x^a)^b = x^(a*b))#

and

#color(blue)(x = x^1)#

Therefore:

#(4xy^2)^3 -> (4^1x^1y^2)^3 -> 4^(1*3)x^(1*3)y^(2*3) ->#

#4^3x^3y^6 - 64x^3y^6#