Question

How do you express `log_3 10` in terms of common logs?

Answer 1

I changed base to base `10`:

Explanation:

You can change base, remembering that if you want to change base, say, from `b` to `c`, you have:
`log_b(x)=(log_c(x))/(log _c(b))`
In your case we can write:
`log_3(10)=(log_(10)(10))/(log_(10)(3)`
Changing into base `10`.

Now you can evaluate the numerator by yourself....try it!