How do you find the exact value of #ln(1/sqrte)#?

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Answer 1 · 2016-12-30T12:28:25

#-1/2#

ln and e are inverse functions.

Each operator is the inverse of the other.

ln(e^a)=a.

Here,

#ln(1/sqrte)#

#=ln(e^(-1/2))#

#=-1/2#.