How do you solve #7( 4x - 3) = 13x + 15+ 9x#?

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Answer 1 · 2016-12-31T08:05:43

#x=6#. See below.

We will simplify the equation, then isolate the variable, #x#.

Begin by combining like terms on the right hand side of the equation:

#7(4x-3)=color(blue)(13x)+15+color(blue)(9x)#

#=>7(4x-3)=22x+15#

Distribute #7# to each term inside the parentheses on the left hand side (distributive property):

#=>28x-21=22x+15#

Subtract #22x# from both sides:

#=>28x-22x-21=cancel(22x-22x)+15#

#=>6x-21=15#

Add #21# to both sides:

#=>6xcancel(-21+21)=15+21#

#=>6x=36#

Divide both sides by 6:

#=>x=6#