How do you solve ${log}_{2} (20 x (x - 11))$ $log_2( 20x ( x - 11) )$ ?

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Answer 1 · 2016-12-31T15:09:59

This is not an equation. Please see the explanation.

${log}_{2} (20 x (x - 11))$ $log_2(20x(x - 11))$ is an expression; not an equation, therefore, it cannot be be solved.

If you are looking for the expression in a more useful form, then I will give you:

$\frac{ln (20) + ln (x) + ln (x - 11)}{ln (2)}; x > 11$ $(ln(20) + ln(x) + ln(x - 11))/ln(2); x > 11$

How do you solve log_2( 20x ( x - 11) )log2(20x(x−11))log_2( 20x ( x - 11) )?