How do you solve #log_2( 20x ( x - 11) )#?

1 Answer
Douglas K.
Dec 31, 2016

This is not an equation. Please see the explanation.

Explanation:

#log_2(20x(x - 11))# is an expression; not an equation, therefore, it cannot be be solved.

If you are looking for the expression in a more useful form, then I will give you:

#(ln(20) + ln(x) + ln(x - 11))/ln(2); x > 11#

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