How do you find the product #-6(-8)(11)#? Prealgebra Negative Numbers and Absolute Value Negative Numbers 1 Answer Meave60 Jan 1, 2017 The product is #528# Explanation: #-6(-8)(11)=# #-6xx-8xx11=528# When two negative numbers are multiplied, the product is positive. Answer link Related questions How do you compute #-8+13#? How do you compute #11+(-19)#? How do you compute #-19-8#? How do you compute #-77+(-46)#? How do you compute #41+(-56)#? How do you compute #50-82#? How do you compute #-47-13#? How do you compute #-80+102#? How do you compute #5(18)#? How do you compute #-64div(-8)#? See all questions in Negative Numbers Impact of this question 2007 views around the world You can reuse this answer Creative Commons License