Question

How do you solve `(2x ^ { 3} + 2x ^ { 2} + 2x ) \div 4x ^ { 3}`?

Answer 1

`1/2(1 + (x + 1)/(x^2))`

Explanation:

`(2x^3 + 2x^2 + 2x) div 4x^3`

`=> (2x(x^2 + x + 1))/(4x(x^2))`

`=> (2x)/(4x)*(x^2 + x + 1)/(x^2)`

`=> (1/2)(x^2/x^2 + x/x^2 + 1/x^2)`

`=> (1/2)(1 + (x + 1)/x^2)`