How do you evaluate #\sqrt { 25} - 9\cdot 2^ { 3}#?

1 Answer
Jan 2, 2017

The answer is #-67#.

Explanation:

Order of operations precedence rules say to evaluate the power #2^3# before multiplying it by 9, so #9*2^(3)=9*8=72#.

Since #sqrt(25)=5# (take just the positive square root when you see this symbol in this context), it follows that #sqrt(25)-9*2^(3)=5-72=-67#.