How do you solve #-5x \leq - 8x + 21#?
1 Answer
Jan 3, 2017
Explanation:
Collect terms in x on the left side of the inequality.
add 8x to both sides.
#-5x+8x<=cancel(-8x)cancel(+8x)+21#
#rArr3x<=21# To solve for x, divide both sides by 3
#(cancel(3) x)/cancel(3)<=21/3#
#rArrx<=7" is the solution"#
