Question

Question #f2dad

Answer 1

1 . The yield will decrease; 2. There will be no effect on the yield.

Explanation:

1. Using 80 % propan-1-ol

I'm guessing that you are making the propyl ester of a carboxylic acid and then titrating the reaction mixture to determine how much acid remains at the end of the esterification.

`underbrace("RCOOH")_color(red)("carboxylic acid") + underbrace("CH"_3"CH"_2"CH"_2"OH")_color(red)("propan-1-ol") stackrelcolor(blue)("H"^"+"color(white)(m))(⇌) underbrace("RCOOCH"_2"CH"_2"CH"_3)_color(red)("a 1-propyl ester") + "H"_2"O"`

The esterification is an equilibrium reaction in which water is a reaction product.

If you start with 80 % propan-1-on instead of anhydrous propan-1-ol, you are adding extra water to the mixture.

Per Le Châtelier's Principle, you will be shifting the position of equilibrium to the left and decreasing the yield of the ester.

2. Changing the concentration of `"NaOH"` used for titration will have no effect on the yield.

You are using the `"NaOH"` solution to determine the amount of acid remaining at the end of the reaction.

Changing the concentration will change the volume of titrant used to neutralize the acid, but it will have no effect on the amount of acid present.