How do you use the properties of logarithms to expand $lnxyz^2$ ?

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Answer 1 · 2017-01-07T06:27:55

$lnx+lny+2lnz$

Since

$log(ab)=loga+logb$ ,

then

$ln(xyz^2)=lnx+lny+lnz^2$

and, since

$loga^b=bloga$

then the given expression is:

$lnx+lny+2lnz$

How do you use the properties of logarithms to expand lnxyz^2lnxyz^2?