How do you expand #Ln (xyz^2)#?

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Answer 1 · 2017-01-08T21:47:03

#ln(xyz^2)=lnx+lny+2lnz#

Since

#ln(ab)=lna+lnb#,

you get:

#ln(xyz^2)=lnx+lny+lnz^2#.

Since

#lna^b=blna#,

you get:

#ln(xyz^2)=lnx+lny+2lnz#