How do you factor completely $P(v)=v^3+v^2-16v-16$ ?

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Answer 1 · 2017-01-09T18:40:09

The answer is $=color(red)((v+1))color(blue)((v-4)(v+4))$

We use

$a^2-b^2=(a+b)(a-b)$

$P(v)=v^3+v^2-16v-16$

$=v^2color(red)((v+1))-16color(red)((v+1))$

$=color(red)((v+1))color(blue)((v^2-16))$

$=color(red)((v+1))color(blue)((v-4)(v+4))$

How do you factor completely P(v)=v^3+v^2-16v-16P(v)=v^3+v^2-16v-16?