How do you solve #E/7=10/14#?

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Answer 1 · 2017-01-10T02:28:28

You use: #A/B=C/DharrA*D=B*C# (cross-multiply)

#->E*14=7*10->E=(7*10)/(14)=(cancel7*cancel2*5)/(cancel2*cancel7)=5#

Check : #5/7=10/14#

Answer 2 · 2017-01-10T02:30:06

Move all of the constants to one side of the equation with algebraic operations just as with and equality.

#(E/7) * 7 = (10/14) * 7#

#E = (10/2)# ; E = 5

CHECK: #(5/7) = (10/14)# ; #(5/7) * (2/2) = (10/14)#

#(10/14) = (10/14)# Correct.