Question

How many moles are present in a `100*g` mass of acetic acid?

Answer 1

`"Number of moles of acetic acid"` `=` `5/3*mol`

Explanation:

`"Moles of acetic acid"` `=` `"Mass"/"Molar mass"`

`(100*cancelg)/(60.05*cancelg*mol^-1)=??mol`