If #pOH=10.75#, what is the concentration of #[HO^-]# in the solution? Chemistry Solutions Molarity 1 Answer anor277 Jan 10, 2017 #[HO^-]=1.78xx10^-11*mol*L^-1.# Explanation: #pOH=-log_10[HO^-]# If #pOH=10.75#, then #[HO^-]=10^(-10.75)=1.78xx10^-11*mol*L^-1.# What are #pH#, and #[H_3O^+]# in this solution? Answer link Related questions what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... How can molarity and osmolarity be calculated from mass per unit volume? How can molarity be used as a conversion factor? How high can molarity be? How does molarity change with temperature? How do you find molarity of a solution? What is the molarity of 10 NaOH? What is the molarity of 3 hydrogen peroxide? What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? What is molarity? See all questions in Molarity Impact of this question 3134 views around the world You can reuse this answer Creative Commons License