Two urns each contain green balls and blue balls. Urn I contains 4 green balls and 6 blue balls, and Urn ll contains 6 green balls and 2 blue balls. A ball is drawn at random from each urn. What is the probability that both balls are blue?

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Answer 1 · 2017-01-10T19:38:29

The answer is #=3/20#

Probability of drawing a blueball from Urn I is

#P_I=color(blue)(6)/(color(blue)(6)+color(green)(4))=6/10#

Probability of drawing a blueball from Urn II is

#P_(II)=color(blue)(2)/(color(blue)(2)+color(green)(6))=2/8#

Probability that both balls are blue

#P=P_I*P_(II)=6/10*2/8=3/20#

Tony B with Guidance from Alan P