Question

How do you condense `2ln8+5ln(z-4)`?

Answer 1

`ln(8^2(z-4)^5)`

Explanation:

We have:

`2ln8+5ln(z-4)`

We can use the rule that `xlny=lny^x` to rewrite this:

`ln8^2+ln(z-4)^5`

We can then use the rule that `lnA + lnB=ln(AB)` to rewrite:

`ln(8^2(z-4)^5)`