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Question #24cce

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Jan 11, 2017

#int_a^bsin(x)dx=lim_(n->oo)(b-a)/nsum_(k=0)^nsin(a+k/n(b-a))#

Explanation:

#int_a^bsin(x)dx=lim_(n->oo)(b-a)/nsum_(k=0)^nsin(a+k/n(b-a))#

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