Question

What is the antiderivative of `e^-x`?

Answer 1

`int \ e^(-x) \ dx = -e^(-x) + C`

Explanation:

Using

`d/dx e^(ax) = ae^(ax) => int \ e^(ax) \ dx= 1/ae^(ax)`

Then,

`int \ e^(-x) \ dx= 1/(-1)e^(-x) + C`
`" "= -e^(-x) + C`