How do you integrate #int tcosht# using integration by parts?

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Answer 1 · 2017-01-12T18:25:03

#tsinht-cosht+C#

It is important to know the IBP formula

#I=intuv'dx=uv-intvu'dx#

#I=inttcoshtdt#

#u=t=>u'=1#

#v'=cosht=>v=sinht#

#I=tsinht-intsinhtdt#

#I=tsinht-cosht+C#