Question

How do you evaluate the definite integral `int (e^(2x)) dx` from `[0,1]`?

Answer 1

Using the Fundamental Theorem of Calculus,
`int_0^1 e^(2x)dx=[e^(2x)/2]_0^1=1/2[e^2-e^0]`
`=1/2(e^2-1).`