Question

How do you find `a_7` if `a_n=12(1/2)^(n-1)`?

Answer 1

`a_7 = 3/16`

Explanation:

`a_n = 12(1/2)^(n - 1)`

`=> a_7 = 12(1/2)^(7 - 1)`

`=> a_7 = 12(1/64)`

`=> a_7 = 3/16`