How do you determine if #f(x) = 6x^5 -5x# is an even or odd function?

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Answer 1 · 2017-01-16T10:09:44

#f(x)# is odd.

an odd function is defined as: #f(-x)=-f(x)#

an even function is defined as: #f(-x)=f(x)#

#f(x)=6x^5-5x#

#f(-x)=6(-1)^5-5(-x)#

#f(-x)=-6x+5(x)#

#f(-x)=-(6x^5-5x)=-f(x)#

#:.#odd