A projectile is shot from the ground at an angle of #pi/4 # and a speed of #7 m/s#. Factoring in both horizontal and vertical movement, what will the projectile's distance from the starting point be when it reaches its maximum height?

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Answer 1 · 2017-01-16T16:30:55

The answer is #=2.5m#

Resolving in the vertical direction #uarr^+#

#u=7 sin(pi/4)ms^-1#

#v=0#

#a=-9.8m^(-1)#

We use the equation

#v=u+at#

#0=7sin(pi/4)-9.8*t#

#t=7/9.8*sin(pi/4)=0.505s#

Resolving in the #rarr^+#

#u=7cos(pi/4)ms^-1#

#x=7cos(pi/4)*0.505=2.5m#