Question

Are those five different ways of receiving Al2(SO4)3 correct?

I tried to do it myself, but I'm not sure if those reactions are correct.

1) Acid + Base
3H2SO4 + 2Al(OH)3 ​→ Al2(SO4)3 + 6H2O

2) Acid + Metal
2Al + 3H2SO4 ​→ Al2(SO4)3 + 3H2

3) metal oxide + metal oxide
3SO3 + Al2O3 ​→ Al2(SO4)3

4) Acid + metal oxide
3H2SO4 + Al2O3 ​→ Al2(SO4)3 + 3H2O

5) Salt + Acid
3H2SO4 + 2Al(NO2)3 ​→ Al2(SO4)3 + 6HNO2

Answer 1

Yes, they should all work.

Explanation:

The driving force for reactions 1) and 4) is the formation of the weak electrolyte, `"H"_2"O"`.

The driving force for reaction 2) is the formation of the gas, `"H"_2`, which escapes into the atmosphere.

The driving force for reaction 5) is the formation of the weak electrolyte, `"HNO"_2`.

I was initially worried about reaction 3) but, if the reaction is carried out in aqueous media, the `"SO"_3` would react with water to form `"H"_2"SO"_4`, and then you would have reaction 4).