Question

How do you simplify `20(cos((7pi)/6)+isin((7pi)/6))div15(cos((11pi)/3)+isin((11pi)/3))` and express the result in rectangular form?

Answer 1

`= - 4/3 i`

Explanation:

In polar complex, that's:

`(20 e^(i(7 pi)/6))/(15 e^(i (11 pi)/3))`

`= 4/3 e^(-(5 pi)/2)`

`= 4/3 e^(-( pi)/2)`

`= - (4i)/3`