A charge of #36 C# passes through a circuit every #4 s#. If the circuit can generate #72 W# of power, what is the circuit's resistance?
1 Answer
Jan 17, 2017
The resistance is
Explanation:
If a charge
#I=Q/t=36/4=9A#
From the known power we can calculate the voltage:
#P=UxxI =>U=P/I#
#U=72/9=8V#
Now we can calculate the resistance: