Question

An object with a mass of `7 kg` is hanging from a spring with a constant of `3 (kg)/s^2`. If the spring is stretched by `2 m`, what is the net force on the object?

Answer 1

The net force `=62.6N`

Explanation:

We use Hooke's law

`F=kx`

`x=2m`

`k=3kgs^-2`

`F=3*2=6N`

The net force `=7g-6=62.6N`