Question

How do you write `y-3=2.5(x+1)` in standard form?

Answer 1

`2.5x-y+5.5=0`

Explanation:

The equation of a line in `color(blue)"standard form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(ax+by+c=0)color(white)(2/2)|)))`

Rearrange `y-3=2.5(x+1)" into this form"`

distribute the bracket.

`rArry-3=2.5x+2.5`

subtract y from both sides.

`cancel(y)cancel(-y)-3=2.5x-y+2.5`

`rArr0-3=2.5x-y+2.5`

add 3 to both sides.

`0cancel(-3)cancel(+3)=2.5x-y+2.5+3`

`rArr2.5x-y+5.5=0larrcolor(red)" in standard form"`