Question

Question #d67e3

Answer 1

`1`.

Explanation:

Since, `x:y=1:2," let us take, "m/_x=theta, m/_y=2theta`.

But, `x & y" are complementary, "m/_x+m/_y=90^@`.

`:. theta+2theta=90^@ rArr theta=30^@`

`rArr m/_x=30^@, m/_y=60^@`.

`rArr sinx+cosy=sin30^@+cos60^@=1/2+1/2=1`.

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