How do you write #y + 9 = -3(x - 2) # in standard form?

1 Answer
Jan 23, 2017

#3x+y+3=0#

Explanation:

The equation of a line in #color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(ax+by+c=0)color(white)(2/2)|)))#

Rearrange #y+9=-3(x-2)" into this form"#

distribute the bracket.

#y+9=-3x+6#

add 3x to both sides.

#y+3x+9=cancel(-3x)cancel(+3x)+6#

#rArry+3x+9=6#

subtract 6 from both sides.

#y+3x+9-6=cancel(6)cancel(-6)#

#rArr3x+y+3=0larrcolor(red)" in standard form"#