How do you write #y + 9 = -3(x - 2) # in standard form?
1 Answer
Jan 23, 2017
Explanation:
The equation of a line in
#color(blue)"standard form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(ax+by+c=0)color(white)(2/2)|)))# Rearrange
#y+9=-3(x-2)" into this form"# distribute the bracket.
#y+9=-3x+6# add 3x to both sides.
#y+3x+9=cancel(-3x)cancel(+3x)+6#
#rArry+3x+9=6# subtract 6 from both sides.
#y+3x+9-6=cancel(6)cancel(-6)#
#rArr3x+y+3=0larrcolor(red)" in standard form"#