How do you solve the system of equations #3x - 9y = 0# and #8x - 2y = 66#?

1 Answer
Jan 24, 2017

#x=9# and #y=3#

Explanation:

#3x-9y=0#
#8x-2y=66#

Reduce the first equation to get a value for #x#.

#3x-9y=0#

Add #9y# to both sides.

#3x=9y#

Divide all terms by #3#.

#x=3y#

In the second equation, substitute #x# with #color(red)3y#.

#8x-2y=66#

#8(color(red)3y)-2y=66#

Open the brackets and simplify.

#24y-2y=66#

#22y=66#

Divide both sides by #22#.

#y=3#

In the first equation, substitute #y# with #color(blue)3#.

#3x-9y=0#

#3x-9(color(blue)3)=0#

Open the brackets and simplify.

#3x-27=0#

Add #27# to both sides.

#3x=27#

Divide both sides by #3#.

#x=9#