Question

How do you solve `abs(14-3x)>18`?

Answer 1

Solution: `x < -4/3 or x > 32/3`
In interval notation: `( -oo , - -4/3) uu ( 32/3 , oo)`

Explanation:

`| 14 - 3 x | > 18 or 14 - 3 x > 18 or - 3 x > 18-14 or -3 x > 4 or 3 x < -4 or x < -4/3` OR

`| 14 - 3 x | > 18 or 14 - 3 x < -18 or - 3 x < -18-14 or -3 x < -32 or 3 x > 32 or x > 32/3`

Solution: `x < -4/3 or x > 32/3`
In interval notation: `( -oo , - -4/3) uu ( 32/3 , oo)`[Ans]