Suppose a treadmill has an average acceleration of #4.7 * 10^-3# #m##/##s^2#. How much does its speed change after #5.0# min? If the treadmill's initial speed is #1.7# #m##/##s#, what will its final speed be?

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Answer 1 · 2017-01-24T14:41:57

Final velocity =3.11m/s

First of all lets see what is given

#a=4.7*10^-3##m/s^2#=#0.0047m/s^2#
#t=5 min=5*60=300s#
#u=1.7m/s#
#v=?#

Remember its a tip that if you write this given part so systematically its really not a waste of TIME.

now ,by this part we can easily choose the formula

#a=(v-u)/t#
#0.0047=(v-1.7)/300#
#1.41=v-1.7#
#v=3.11m/s#