How do you solve #2x + 3 = 63#?

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Answer 1 · 2017-01-25T16:06:43

See the entire solution process below:

First, subtract #color(red)(3)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#2x + 3 - color(red)(3) = 63 - color(red)(3)#

#2x + 0 = 60#

#2x = 60#

Now, divide each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#(2x)/color(red)(2) = 60/color(red)(2)#

#(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = 30#

#x = 30#