How do you solve #6x-13=2x + 7#?

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Answer 1 · 2017-01-26T14:27:58

See the entire solution process below:

First, subtract #color(red)(2x)# and add #color(blue)(13)# to each side of the equation to isolate the #x# terms and keep the equation balanced:

#6x - 13 - color(red)(2x) + color(blue)(13) = 2x + 7 - color(red)(2x) + color(blue)(13)#

#6x - color(red)(2x) - 13 + color(blue)(13) = 2x - color(red)(2x) + 7 + color(blue)(13)#

#6x - color(red)(2x) - 0 = 0 + 7 + color(blue)(13)#

#(6 - 2)x = 20#

#4x = 20#

Now divide each side by #color(red)(4)# to solve for #x#:

#(4x)/color(red)(4) = 20/color(red)(4)#

#(color(red)(cancel(color(black)(4)))x)/cancel(color(red)(4)) = 5#

#x = 5#