Question

What mass of oxygen is required to make `90*g` of `NO`?

Answer 1

Approx. `42*g`

Explanation:

We could assume either atoms or molecules; for this problem it is wise to use atomic mass.

`"Atoms of oxygen"-=(48*g)/(16.00*g*mol^-1)=3.0*mol*"oxygen atoms, i.e "3xxN_A" oxygen atoms."`

So we need `3.0*mol` `"nitrogen atoms"`, or `3xxN_A` `"nitrogen atoms,"` which has an equivalent mass of,

`3*molxx14.01*g*mol^-1=??*g`