For #f(x) = .01(2)^x#, how do you find the average rate of change from #x=12# to #x=15#?

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Answer 1 · 2017-01-27T03:06:20

81.92

Formula to remember :

The average rate of change

#=( int f' dx)/(b-a)#, with x from a to b.

#=[f]/(b-a)#, between x = a and b.

#=(f(b)-f(a))/(b-a)#.

Here, it is

(-01 )(2^15 - 2^13)/(15-13)#

#=81.92#