How do you solve #4-12n-14 > 8n +12 -9n#?

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Answer 1 · 2017-01-27T05:38:09

#n<-2#

First, you could transfer the n-terms to the left and the known terms to the right, taking care of changing the signs to the transferred terms:

#-12n-8n+9n> -4+14+12#

then sum the like terms:

#-11n>22#

then change the signs and the behavior:

#11n<-22#

and divide right and left terms by 11:

#n<-2#

that's, in the interval form, if #n in RR#:

#n in]-oo;-2[#