How do you solve #5(6+3r)+7>=127#?
1 Answer
Jan 30, 2017
Explanation:
First step is to distribute the bracket.
#rArr30+15r+7>=127#
#rArr15r+37>=127# Isolate 15r by subtracting 37 from both sides of the inequality.
#15rcancel(+37)cancel(-37)>=127-37#
#rArr15r>=90# To solve for r, divide both sides by 15
#(cancel(15) r)/cancel(15)>=90/15#
#rArrr>=6" is the solution"#
