How do you solve #4x ^ { 2} - 4x + 2= x ^ { 2} + 6x - 6#?

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Answer 1 · 2017-01-30T19:01:33

#x=4/3 = 1 1/3# or #x=2#

#4x^2-4x+2=x^2+6x-6#

#:.4x^2-x^2-4x-6x=-6-2#

#:.3x^2-10x=-8#

#:.3x^2-10x+8=0#

#:.(3x-4)(x-2=0)#

#:.3x=4 , x=2#

#:.x=4/3 , x=2#

substitute #x= 4/3#

#:.4(4/3)^2-4(4/3)+2=(4/3)^2+6(4/3)-6)#

#:.4(16/9)-16/3+2=16/9+24/3-6#

#:.64/9-16/3+2/1=16/9+24/3-6/1#

#:.(64-48+18=16+72-54)/9#

#:.34=34#

substitute #x= 2#

#:.4(2)^2-4(2)+2=(2)^2+6(2)-6#

#:.16-8+2=4+12-6#

#:.10=10#