Question #ce46f
1 Answer
Explanation:
The key to this problem is the specific heat of olive oil, which is said to be equal to
#c_"olive oil" = "2.19 cal g"^(-1)""^@"C"^(-1)#
As you know, the specific heat of a substance tells you how much heat must be added to
In your case, you must add
Now, the first thing to do here is to figure out how much heat is needed in order to increase the temperature of
#55.0 color(red)(cancel(color(black)("g"))) * "2.19 cal"/(1color(red)(cancel(color(black)("g"))) * 1^@"C") = "120.45 cal"^@"C"^(-1)#
This means that in order to increase the temperature of
Consequently, adding
#877 color(red)(cancel(color(black)("cal"))) * overbrace( (1^@"C")/(120.45color(red)(cancel(color(black)("cal")))))^(color(blue)("for 55.0g of olive oil")) = 7.28^@"C"#
Therefore, the final temperature of the olive oil will be
#color(darkgreen)(ul(color(black)(T_"final" = 26.0^@"C" + 7.28^@"C" = 33.3^@"C")))#
The answer is rounded to three sig figs.